6x +30 -3x +6 =12x +18
3x +36 =12x +18
3x-12x = 18 -36
-9x = -18 | -1
9x =18
x= 18/9
x=2
Answer:
The width of the rectangle is the same as the length of the cylinder (h). The area of each of the two circles is \\ (\\pi r^2\\) and the area of the rectangle is \\ (2 \\pi r times h\\).
Step-by-step explanation:
Answer:
Rosa ran
of the total distance between her house and her school.
Step-by-step explanation:
Distance between Rosa's house and her school =
miles ≈ 4.5 miles
She ran distance = 3 miles
Therefore, fraction of the total distance between her house and school she run = ![\frac{\text{Distance run by Rosa}}{\text{Total distance between her house and school}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BDistance%20run%20by%20Rosa%7D%7D%7B%5Ctext%7BTotal%20distance%20between%20her%20house%20and%20school%7D%7D)
= ![\frac{3}{4.5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4.5%7D)
= ![\frac{30}{45}](https://tex.z-dn.net/?f=%5Cfrac%7B30%7D%7B45%7D)
= ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Therefore, Rosa ran
of the total distance between her house and her school.
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: motor skills of a sober subject.
n= 20
X[bar]= 37.1
S= 3.7
The claim is that the average score for all sober subjects is equal to 35.0, symbolically: μ= 35.0
The hypotheses are:
H₀: μ = 35.0
H₁: μ ≠ 35.0
α: 0.01
The statistic to use, assuming all conditions are met, is a one sample t- test
![t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~t_%7Bn-1%7D)
![t_{H_0}= \frac{37.1-35.0}{\frac{3.7}{\sqrt{20} } } = 2.34](https://tex.z-dn.net/?f=t_%7BH_0%7D%3D%20%5Cfrac%7B37.1-35.0%7D%7B%5Cfrac%7B3.7%7D%7B%5Csqrt%7B20%7D%20%7D%20%7D%20%3D%202.34)
This test is two-tailed, meaning, the rejection region is divided in two and you'll reject the null hypothesis to low values of t or to high values of t:
![t_{n-1;\alpha /2}= t_{19; 0.005}=-2.861](https://tex.z-dn.net/?f=t_%7Bn-1%3B%5Calpha%20%2F2%7D%3D%20t_%7B19%3B%200.005%7D%3D-2.861)
![t_{n-1;1-\alpha /2}= t_{19; 0.995}= 2.861](https://tex.z-dn.net/?f=t_%7Bn-1%3B1-%5Calpha%20%2F2%7D%3D%20t_%7B19%3B%200.995%7D%3D%202.861)
The decision rule using this approach is:
If
≤ -2.861 or if
≥ 2.861, you reject the null hypothesis.
If -2.861 <
< 2.861, you do not reject the null hypothesis.
The value is within the non rejection region, the decision is to not reject the null hypothesis.
I hope this helps!