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grandymaker [24]
3 years ago
5

How did the war of 1812 start PLEAEE HELP NOW​

Mathematics
2 answers:
Kitty [74]3 years ago
5 0

Answer:

It started when the u.s attacked Canada and then the British came and burnt the white house.

Step-by-step explanation:

good luck

Tanya [424]3 years ago
3 0

Answer:

In 1812, with President Madison in office, Congress declared war against the British. The war began with an attack on Canada, both as an effort to gain land and to cut off British supply lines to Tecumseh's Indian confederation, which had long troubled the US. ... The US troops were badly routed.

Step-by-step explanation:

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Which of the following shows 12⁄28 written in prime factored form to help in reducing the fraction to simplest form?
mixas84 [53]
The answer would be 3/7

Explanation:
This question is basically asking for you to simplify 12/28. To do this, we find the GCF (Greatest Common Factor) of 12 and 28, which is 4. Then, we do 12 / 4 and 28 / 4, which gives us 3 and 7. Therefore, the answer is 3/7.
3 0
3 years ago
Read 2 more answers
A clothing store has a going-out-of business sale. They are selling pants for $8.99 and shirts for $3.99. You can spend as much
astraxan [27]

Answer:

Let x represents the number of pants and y represents the number of shirts.

As per the statement:

Since, a clothing store are selling pants for $8.99 and shirts for $3.99

then;

total number of Pants cost is, $8.99x and total number of Shirt cost is, $3.99

Also, it is given that: You can spend as much as $60 and want to buy at least two pairs of pants.

then, we have the equation of inequality;

8.99x + 3.99y \leq 60 ;......[1]         where x, y are natural number.

x-intercept:

Substitute the value y= 0  in [1] and solve for x;

8.99x + 3.99(0) \leq 60

8.99x \leq 60

Simplify:

x \leq 6.667

Since, x is in natural number;

x \leq 7

Similarly.

For y-intercept:

Substitute the value x= 0  in [1] and solve for x;

8.99(0) + 3.99y \leq 60

3.99y \leq 60

Simplify:

y \leq 15.037

y \leq 15

Therefore, we have

8.99x + 3.99y \leq 60 ;

2\leq x\leq 7 and  0\leq y\leq 15

8 0
3 years ago
Equation for $.10 times 30 equals three dollars
sukhopar [10]

Answer:

30 (.1)=3

or you could do

30×.1=3

you could use either one but I dont know what the person your turning the work in requires the equation to look like

6 0
3 years ago
Read 2 more answers
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
What is three ways to express 3^5 as a product of powers
schepotkina [342]

Three ways to express it as a product of powers are:

3x3x3x3x3

3^5

243

Hope I helped!

Good Luck!

3 0
3 years ago
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