Answer:
Y = 26
W = 73
X = 81
Step-by-step explanation:
∠W = 3∠Y - 5
∠X = ∠W + 8 = 3∠Y - 5 + 8 = 3∠Y + 3
∠Y + ∠W + ∠X = 180
substitute in the formula
Y + (3Y - 5) + (3Y + 3) = 180
7Y -2 = 180
7Y = 182
Y = 26
W = 3(26) - 5 = 73
X = 73 + 8 = 81
Answer:
C on EdgE
Step-by-step explanation:
2020
Answer:
21 box of books can be brought up by the delivery person at one time
Step-by-step explanation:
Here, we want to know the number of box of books that the delivery person could bring up at one time.
Let the number of boxes be x , so the total mass of the boxes that could come up at a time will be x * 40 = 40x lb
Let’s add this to the mass of the delivery person = 150 lb
So the total mass going inside the lift would be 150 + 40x
So we have to equate this to the maximum capacity of the lift;
150 + 40x = 1020
40x = 1020 - 150
40x = 870
x = 870/40
x = 21.75
Now since we cannot have fractional boxes, the number of boxes that could come into the lift without exceeding the maximum capacity of the lift is 21
Answer:
A. 267.95 cm^2
Step-by-step explanation:
4/3 X 3.14 X 4^3 = 267.946 to 2d.p 267.95
Eighteen million one hundred and sixty five thousand four hundred and eleven.
