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dangina [55]
3 years ago
15

Please help extra points and Mark brainless

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0
-1/6 Is the answer for this!!
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What is the Common Factor<br><br> 3t^5s − 15t^2s^3
Neporo4naja [7]

Answer:

3t^2s

Step-by-step explanation:

15/3=5

t^5s/t^2s = t^3

t^2s^3/t^2s = s^2

3 0
3 years ago
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Can 1 and 3/20 can be simplified?
Scrat [10]
One and 3/20 can't be simplified
7 0
4 years ago
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Photo and Video Sharing. Photos and videos have become an important part of the online social experience, with more than half of
love history [14]

Answer: 0.923

Step-by-step explanation:

Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves.

Pew Research Center finds that

P(A)=0.52    P(b)=0.26,  and P(A or B)=0.54.

To find : P(A|B)

Since , \text{P(A or B)=P(A+P(B)-P(A and B)}

i.e. \text{P(A and B)=P(A)+P(B)-P(A or B)}

\text{P(A and B)=}0.52+0.26-0.54=0.24

Now, using conditional probability formula ,

P(A|B)=\dfrac{\text{P(A and B)}}{\text{P(B)}}\\\\=\dfrac{0.24}{0.26}=0.923076923077\approx0.923

Hence, the conditional probability that an Internet user posts photos that they have taken themselves, given that they post videos that they have taken themselves = 0.923

5 0
4 years ago
Pls help me guys! This is super hard
Mashcka [7]
I count 4 green stars and 6 red stars

ratio of green to red would be
4 green : 6 red

4:6

if you divide both numbers by 2, cause theyre both even

2:3
6 0
3 years ago
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Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
2 years ago
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