3 years ago

S is the midpoint of RT. If RS = 6x + 2 and RT = 10x + 14, write the

Mathematics

1 answer:

nekit [7.7K]3 years ago

5 0

Answer:

To solve for x, we set the two equations equal to each other

6x+2 = 10x+14 We will use inverse operations

2 = 4x+14.

-12 = 4x

x= -3

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Answer: 4.25

Step-by-step explanation:

2(d-3) + 22d= 120-24

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3 years ago

The first sail has one side of length 9 feet and another of length 6 feet. Determine the range of possible lengths of the third

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3 years ago

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Step-by-step explanation:

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2 years ago

\root(3)(-3)\root(3)(-5)=\root(3)(15) true or false

Oksi-84 [34.3K]

The equation $\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$ is true

<h3>How to determine the true statement?</h3>

The equation is given as

$\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$

Apply the law of indices

$\sqrt[3]{-3 * -5} = \sqrt[3]{15}$

Evaluate the product

$\sqrt[3]{15} = \sqrt[3]{15}$

Both sides of the equation are the same

Hence, the equation $\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$ is true