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guajiro [1.7K]
3 years ago
11

What is the area, in square meters, of the isosceles trapezoid below?

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

Where is the triangle?

you might have to add a picture or a worded problem

Step-by-step explanation:

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2/3 + w = 3/2 what is w
lora16 [44]

Answer:

w=0

Step-by-step explanation:

3 0
3 years ago
Find the missing dimension. Use the scale factor 1: 8.
Vanyuwa [196]

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9cm

Step-by-step explanation:if im wrong sorry

5 0
3 years ago
Determime the intercepts of the line that passes through the following points. (-6,5);(-3,3);(0,1)
butalik [34]

well for a line, to get its slope all we need is two points, so let's use (-6, 5) and (0, 1), and get the equation of it.


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\qquad
(\stackrel{x_2}{0}~,~\stackrel{y_2}{1})
\\\\\\
slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-5}{0-(-6)}\implies \cfrac{1-5}{0+6}\implies -\cfrac{5}{6}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-5=-\cfrac{5}{6}[x-(-6)]\implies y-5=-\cfrac{5}{6}(x+6)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\textit{to get the x-intercept, we set y = 0, solve for \underline{x}}
\\\\\\
0-5=-\cfrac{5}{6}(x+6)\implies -30=5x+30\implies -60=5x
\\\\\\
\cfrac{-60}{5}=x\implies -12=x~\hfill \boxed{\stackrel{x-intercept}{(-12,0)}}


now, where's the y-intercept of that line?  well, to get the y-intercept, we set x = 0 and solve for "y"....hmmmm wait a second, notice (0, 1), x = 0, y = 1, that's the y-intercept already.

7 0
3 years ago
Find the missing side:
Oksana_A [137]
66.13!
Hope this helps
7 0
3 years ago
When the sum of 5 and 6 is subtracted from the product of 5 and 6, what's the difference
Mamont248 [21]
<span>5+6=11
5x6=30
30-11+19
answer is 19</span>
4 0
3 years ago
Read 2 more answers
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