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3 years ago

What is the area, in square meters, of the isosceles trapezoid below?

Mathematics

1 answer:

Greeley [361]3 years ago

3 0

Answer:

Where is the triangle?

you might have to add a picture or a worded problem

Step-by-step explanation:

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the size of a rectangular computer screen is determined by the length of its diagonal. tom buys a 52cm screen that is 33 cm high

Snowcat [4.5K]

Answer:

40.20cm approx

Step-by-step explanation:

Step one

given data

We are told that the dimension of a computer screen

diagonal= 52 cm

height= 33cm

Length = ?

Required

The length of the base of the screen

Step two

Let us use Pythagoras theorem to find the length of the base

Hyp^2= Opp^2+ Adj^2

52^2= 33^2+ L^2

2704= 1089+L^2

L^2= 2704-1089

L^2= 1615

L=√1615

L= 40.20cm approx

The length is 40.20cm approx.

8 0

3 years ago

Which pony lies on the line described by the equation below? y + 4 = 4 ( x - 3)

CaHeK987 [17]

(3, -4) is on the line because the equation is point-slope equation where the point (x1, y1) is;
y - y1 = m(x- x1)

5 0

3 years ago

The bacteria has an initial population of 2000 cells and increases at a rate of 40% per hour. Use the exponential function to mo

Fynjy0 [20]

2000% x .4 will give you your answer!

5 0

3 years ago

Read 2 more answers

At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive

OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is $\frac{15}{10}$

and in 60 minutes the number of arrival home team fans is $\frac{15 \times 60}{10}$

=90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team leave.

then in 1 minutes $\frac{5}{10}$ fans leave of away team leave.

and In 60 minutes $\frac{5\times 60}{10}$ =30 fans leave of away team leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0

3 years ago

Help!! Which operation should be used to solve X/3= 15? A= ÷3 B= -3 C=+3 D=x3

Lera25 [3.4K]

Answer: D: X3

Step-by-step explanation:

4 0

3 years ago