Solve for the proportion (type integer or simplified fraction)
1 answer:
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Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ± *
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71
[10.41±1.645*]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer:
The correct answer are given by (A) ; (B)
.
Step-by-step explanation:
Total number of entries to the sweepstakes offered by Gemini Paper Products = 175,000.
Total number of prizes to be awarded includes 1 grand prize, 3 first prizes, 25 second prizes and 400 third prizes = 1 + 3 + 25 + 400 = 429.
(A) Required Probability for a person who has put one entry to win the grand prize is given by the fraction .
(B) Required Probability for a person who has put one entry to win any prize offered is given by .
The answer is x^2-5x-6
Don’t mind my English work in the background
Don’t mind my English work in the background