Answer:
Answer:
Mary's ticket was less than the original price by 12 percent
Step-by-step explanation:
1. Let's calculate the 20% discount price Mary received:
75 - 0.2 * 75 = 75 - 15 = $ 60
The discounted price is $ 60
2. Let's calculate the 10% service fee to the discounted price:
60 + 0.1 * 60 = 60 + 6 = $ 66
The price including the service fee is $ 66
3. Finally, let's calculate the less percentage than the original price:
Let's use the Direct Rule of Three, this way:
Price Percentage
75 100
66 x
**************************
75x = 66 * 100
75x = 6,600
x = 6,600/75
x = 88
Less percentage = 100 - 88 = 12%
Mary ticket was less than the original price by 12 percent
We start with m < A + m < B = m < B + m < C as the given equation. We can rearrange the two terms on the right hand side to get m < A + m < B = m < C + m < B. From here, subtract m < B from both sides to end up with m < A = m < C. The angle B terms go away entirely. This rule I used was the subtraction property of equality. The next rule to use is the symmetric property to go from m < A = m < C to m < C = m < A. This rule is basically where we can flip the two sides of the equation and the equation is the same.
Answer:
The rate of change of function A is greater than the rate of change of function B
Step-by-step explanation:
<u>Function A</u>
For every increase of 1 unit in x-values, the y-values increase by 3 units.
<u>Function B</u>
For every increase of 1 unit in x-values, the y-values increase by 2 units.
As 3 > 2, the rate of change of function A is greater than the rate of change of function B
Divide each side by 4/9 // Multiply the reciprocal, which would be 9/4
Which would leave you with
Answer:
Step-by-step explanation:
The formula for determining confidence interval is expressed as
Confidence interval
= mean ± z × s/ √n
Where
z is the value of the z score
s = standard deviation
n = sample size
a) The 95% confidence level has a z value of 1.96
The 99% confidence level has a z value of 2.58
Since 99% confidence level z value is greater than 95% confidence level z value, if we input it into the formula, it will result to a higher confidence interval. So changing from a 95% confidence level to a 99% confidence level would make a confidence interval wider.
b) The √15 is smaller than the √350. This means that if we make use of the formula, √350 will give a lower confidence interval than that of √15. Therefore, the confidence interval would be narrower changing from a sample size of 15 to a sample size of 350.
c) Applying the formula, a standard deviation of 15 pounds would result to a lower confidence interval than a standard deviation of 20 pounds. Therefore, the confidence interval would be wider changing from a standard deviation of 15 pounds to a standard deviation of 20 pounds.