4m−2+((−8m)(4))(m)−2−8m
=4m+−2+−32m2+−2+−8m
Combine Like Terms:
=4m+−2+−32m2+−2+−8m
=(−32m2)+(4m+−8m)+(−2+−2)
=−32m2+−4m+−4
Answer:
=−32m2−4m−4
<h3>
Answer:</h3>
Width = 20 yards
Length = 25 yards
<h3>
Step-by-step explanation:</h3>
We are given;
- The area of a rectangle as 500 square yards
We are going to take;
- Length = x + 5 yards
- Width = x
But the area of a rectangle = length × width
Therefore;
x × (x +5) = 500
x² + 5x = 500
Rearranging in quadratic manner
x² + 5x - 500 = 0
Solving the quadratic equation;
Using factorization method
(x+25)(x-20) = 0
Therefore;
x = 20 or -25
We take, x = 20
Thus;
Width = 20 yards
Length = 25 yards
Answer:
a=d-r+c
Step-by-step explanation:
Is that what you're trying to ask?
Quadratics always have 2 solutions, a positive and a negative version of the answer
Tan30 = x/7
0.6 =x/7
x = 0.6 x 7
x = 4.2