What is the area of this parallelogram

alright so I got the answer from here but I still can't figure out how we got 12p? can somebody explain step by step pls

Andreas93 [3]

There's no 12p in the simplification

$(2p+3)^{2} =(2p)^{2} +3^{2} = 4p^{2} +9$

3 0

3 years ago

13 students are going on a field trip4 students can ride in each carHow many cars will they need for the field trip?

inessss [21]

Answer:

4

Step-by-step explanation:

1. Divide total number of students by number of students per car (use remainder rather than decimal)

13/4 = 3, remainder 1

In this case, round up because no student can be left behind. 4 cars will be used.

7 0

4 years ago

Read 2 more answers

If Johnny has 4 apples and heather has 6 apples, how many apples will they have together?

sergejj [24]

Answer:

-2

Step-by-step explanation:

4 0

4 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints are

Andrew [12]

The equation of the perpendicular bisector is y = $-\frac{7}{2}$ x + 2

Step-by-step explanation:

Let us revise the relation between the slopes of perpendicular lines

The product of the slopes of two perpendicular lines is -1
That means if the slope of one of them is m, then the slope of the other is $-\frac{1}{m}$
You reciprocal the slope of one and change its sign to find the slope of the other

The mid point of a segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

The perpendicular bisector of a line is the line that intersect it in its mid-point and formed 4 right angles

∵ The end point of a given line are (9 , -3) and (-5 , -7)

∴ $x_{1}=9$ and $x_{2}=-5$

∴ $y_{1}=-3$ and $y_{2}=-7$

- Find the slope of the line by using the rule of the slope $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ $m=\frac{-7-(-3)}{-5-9}=\frac{-7+3}{-14}=\frac{-4}{-14}=\frac{2}{7}$

∴ The slope of the given line is $\frac{2}{7}$

To find the slope of the perpendicular bisector of it reciprocal it and change its sign

∴ The slope of the perpendicular bisector = $-\frac{7}{2}$

∵ The form of the linear equation is y = mx + b, where m is the

slope and b is the y-intercept

- Substitute the value of m in the equation

∴ The equation of the perpendicular bisector is y = $-\frac{7}{2}$ x + b

To find b substitute x and y in the equation by a point on the line

∵ The perpendicular bisector of the given line intersect it at

its midpoint

- Find the mid-point of the given line busing the rule above

∵ $x_{1}=9$ and $x_{2}=-5$

∵ $y_{1}=-3$ and $y_{2}=-7$

∴ The mid-point of the given line = $(\frac{9+(-5)}{2},\frac{-3+(-7)}{2})=(\frac{4}{2},\frac{-10}{2})=(2,-5)$

Point (2 , -5) is also lies on the perpendicular line

∴ x = 2 and y = -5

- Substitute them in the equation

∵ -5 = $-\frac{7}{2}$ (2) + b

∴ -5 = -7 + b

- Add 7 to both sides

∴ 2 = b

- Substitute the value of b in the equation

∴ The equation of the perpendicular bisector is y = $-\frac{7}{2}$ x + 2

The equation of the perpendicular bisector is y = $-\frac{7}{2}$ x + 2

Learn more:

You can learn more about the linear equation in brainly.com/question/11223427

#LearnwithBrainly

8 0

3 years ago

Can someone help with all of of it ??

Bad White [126]

Answer:

y = -2x + 1

Step-by-step explanation:

First we're going to find the gradient (the number in the green box with the question mark).

We use the formula $\frac{y2-y1}{x2-x1}$ to calculate the gradient.

Let's make (-1, 3) be our (x1, y1), and (2, -3) be our (x2, y2).

Substitute the points into our formula:

gradient = $\frac{(-3)-3}{2- (-1)}$

gradient = $\frac{-6}{3}$

gradient = -2

Next, we're going to find the y-intercept (the number in the grey box)

Now that we have the gradient, our equation looks like this:

y = -2x + c

We use the letter c to represent the y-intercept of a linear graph.

Substitute one of the points given into the x and y in the equation. Let's use (-1, 3).

3 = -2(-1) + c

3 = 2 + c

c = 1

So our equation is y = -2x + 1

8 0

3 years ago