Answer:
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Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable:
Therefore,
Variance of binomial random variable:
Therefore,
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
First, you need to find where you can move the decimal point to so that there is only one non-zero digit to the left of it.
Move the decimal point, and that is the first part done.
Add "".
For the last part - the power, you need to find how many decimal places you moved the decimal point. In this case, we moved it to the right 2 places, so the power is .
If, for example, we had moved the decimal point three places to the left, the power would be .
Answer:
Step-by-step explanation:
We are given that a number 18234
We have to find the prime factorization of the number
Prime factorization : The number written is in the product of prime numbers is called prime factorization.
In order to find the prime factorization we will find the factors of given number
Hence, the prime factorization of
10LW=V
L/10W= V/10W
L= V/10W