The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P, 
, where 
. The slope of the secant line through P and Q is given by the difference quotient,
where we are allowed to simplify because 
.
Then the equation of the secant line is
Taking the limit as 
, we have
so the slope of the line tangent to the curve at P as slope 2.
- - -
We can verify this with differentiation. Taking the derivative, we get
and at 
, we get a slope of 
, as expected.
Answer:
just look at the decimal after the decimal number is the tenths place the hundreds place and so on if i have to round 567.1092 i would round the nine up to make the zero a one so my rounded answer would be 567.11
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
Y2-y1/x2-x1
5-5/9-10 =0/-1. Slope is 0
Answer:
x=1+i√19,1-i√19
Step-by-step explanation:
Write the problem as a mathematical expression.
Subtract from both sides of the equation.
Use the quadratic formula to find the solutions.
Substitute the values, and into the quadratic formula and Simplify.
Simplify the numerator. Multiply by Simplify
Answer:
It ends up being 19 in total
