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2 years ago

Find the value of X.

Mathematics

1 answer:

-Dominant- [34]2 years ago

6 0

To find the value of x we first need to find the missing angle in the triangle.

To do that we are gonna add the angles we already have.

64 + 45 = 109

Angles in a triangle measures 180 so to get the missing angle we are gonna subtract 109 from 180

180 - 109 = 71 deg

The missing angle in the triangle is 71 deg

Angles on a straight line adds up to 10 so to find x we are gonna subtract 71 from 180

180 - 71 = 109 degrees

Therefore x is 109 degrees.

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rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2),

Sholpan [36]

Answer:

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

$\textrm{Perimeter of Rectangle}=2(Length+Width)$

Length = AB

Width = BC

Now By Distance Formula we have'

$l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}$

$l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit$

Similarly

$l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}$

$l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit$

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values in Perimeter we get

$\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit$

Therefore Perimeter of Rectangle ABCD is 4 units

8 0

2 years ago

P: 2,012

OleMash [197]

El volumen remanente entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen remanente entre el espacio de una caja cúbica y una esfera introducida en el elemento anterior. El volumen remanente es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³