You will factor out the common factor of t if you are solving for t. you will then divide both sides by (s+3) to make t the subject of the formula. for this question you can only get t in terms of s.
so:
st+3t=6
t(s+3)/(s+3)=6/(s+3)
t=6/(s+3)
if you are required to solve for s then you are going to subtract 3t from both sides. you can factorise 6-3t .you will then divide both sides by t to isolate s.for this question you can only get s in terms of t.so:
st+3t-3t=6-3t
st/t=2(3-t)/t
s=2(3-t)/t
Well, let's first find our rate of bags to meters.
If 12 bags of plaster covers 54m^2, then we need to divide 54 by 12 to figure out how many meters 1 bag of plaster covers. We will then use that rate and divide 36 by it in order to solve for how many bags of plaster is required.
54 / 12 = 4.5.
This means each bag of plaster covers 4.5m^2.
Divide 36 by 4.5;
36 / 4.5 = 8.
This means that we will need 8 bags of plaster to cover 36m^2.
I hope this helps!
-12 and -1 are 11 units apart.
-12-(-1) = -11
The absolute value which is just the number of units is 11.
Hope this helps you
