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3 years ago

Help please ASAP. Correct answer will get brainly

Mathematics

2 answers:

ExtremeBDS [4]3 years ago

7 0

I think it’s (3,6) too but not sure... I’m sorry if wrong

djverab [1.8K]3 years ago

4 0

Answer:

I think it's 3,6.....................

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I NEED HELP PLS i don’t understand exactly how to do this :/

Sholpan [36]

Answer:

I assume AC = 49.89 since the number is cut off

Step-by-step explanation:

tangent(degree) = opposite / adjacent

To find AC, you can set up tan(29) = AC / CB

tan(29) = AC / 90 (the picture is cutted off, so I assume....)

$90*tan(29)$ = AC

4 0

3 years ago

Can someone help me with this pls (Algebra 2)

azamat

Answer:

5ab - 8a - 5b - 8

Step-by-step explanation:

each of these can be divided by 5

7 0

3 years ago

The formula for centripetal acceleration, a, is given below, where v is the velocity of the object and r is the object's distanc

julsineya [31]

Answer:

Step-by-step explanation:

For this case we have the following equation:

a = v ^ 2 / r

From here, we must clear the value of speed.

We have then:

v ^ 2 = a * r

v = root (a * r)

Answer:

the formula for the velocity is:

v = root (a * r)

3 0

3 years ago

Read 2 more answers

Please help me out please please !!!!!

Sauron [17]

The surface area of a sphere is given by

$S = 4\pi r^2$

We deduce

$r = \sqrt{\dfrac{S}{4\pi}}$

So, in your case, the radius is

$r = \sqrt{\dfrac{100\pi}{4\pi}}=\sqrt{25}=5$

The volume of a sphere is given by

$V=\dfrac{4}{3}\pi r^3$

So, we have

$V = \dfrac{4}{3} \pi 5^3 = \dfrac{500}{3}\pi$

5 0

3 years ago

Combine the following expressions.

Keith_Richards [23]

Answer:

second option

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals

$\sqrt{27x^{3} }$

= $\sqrt{9(3)x^2.x}$

= $\sqrt{9}$ × $\sqrt{3}$ × $\sqrt{x^2}$ × $\sqrt{x}$

= 3 × $\sqrt{3}$ × x × $\sqrt{x}$

= 3x $\sqrt{3x}$

-------------------------------

$\sqrt{12x^{3} }$

= $\sqrt{4(3)x^2.x}$

= $\sqrt{4}$ × $\sqrt{3}$ × $\sqrt{x^2}$ × $\sqrt{x}$

= 2 × $\sqrt{3}$ × x × $\sqrt{x}$

= 2x $\sqrt{3x}$

---------------------------------------

Thus

3 × 3x $\sqrt{3x}$ - 2 × 2x $\sqrt{3x}$

= 9x $\sqrt{3x}$ - 4x $\sqrt{3x}$

= 5x $\sqrt{3x}$

8 0

3 years ago