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3 years ago

PLEASSSEEE HELLPPP

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

D: 14q + 21√qr

Step-by-step explanation:

We want to find the product of;

(2√q + 3√r) and 7√q.

Where p and q are integers.

Using distributive property, we have;

(2√q × 7√q) + (3√r × 7√q)

>> 14q + 21√qr

Correct option is D

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The length of a rectangle is 5 inches longer than it is wide. If the area is 150 square inches, what are the dimensions of the r

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Answer:

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Step-by-step explanation:

Let the width be w.

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3 years ago

Read 2 more answers

Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)

lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

$y + 3 = \frac{1}{2}(x-6)$

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or $y-y_1 = m (x-x_1)$ format. Remember that the number in place of the $m$ is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction ( $-\frac{2}{1}$ ), and flip its numerators and denominators. Therefore, the perpendicular slope would be $\frac{1}{2}$ .

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, $y-y_1 = m (x-x_1)$ . In order to write an equation, the $x_1$ , $y_1$ , and $m$ have to be substitute for with real values.

The $m$ represents the slope. We already calculated that in the last step, so put $\frac{1}{2}$ in place of the $m$ . The $x_1$ and $y_1$ represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for $x_1$ and -3 for $y_1$ :

$y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)$

Therefore, (again, assuming that the line can be put in point-slope form) the answer is $y + 3 = \frac{1}{2}(x-6)$ .

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