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Fudgin [204]
3 years ago
10

Would appreciate some help with this question, I am struggling!

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0
I think you would multiply 14m x 9m which is 126m and then you would multiply 2.4m and 3.8m which is 9.12m. Last you would subtract 9.12m from 126m which is 116.88m...I’m sry if this isn’t correct
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Simplify (x^6)^2 • x^3
givi [52]

Answer:

x^15

Step-by-step explanation:

Recall these rules of exponents:

(a^m)^n = a^mn

a^m • a^n = a^(m + n)

(x^6)² • x³ = x^(2 • 6) • x³ = x^12 • x³ = x^(12 + 3) = x^15

8 0
2 years ago
What is the answer to x-5?
Thepotemich [5.8K]

Answer: x=5

Step-by-step explanation:

i’m not sure if that’s what you meant. there’s not much info.

8 0
3 years ago
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Which is the graph of y = log (negative x)?
Yanka [14]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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Amlyah increased her bench press
NikAS [45]
<h3>Answer:  20% increase</h3>

======================================================

Explanation:

A = old value = 110

B = new value = 132

C = percent change

C = 100*(B-A)/A

C = 100*(132-110)/110

C = 20%

The positive C value means we have a percent increase, which corresponds to the fact that A = 110 increases to B = 132.

The B-A = 132-110 = 22 portion up top indicates that the increase is 22 pounds, which when divided over 110, gets us 22/110 = 0.20 = 20%

---------------

Checking the answer:

20% of 110 = 0.20*110 = 22

She's able to lift 22 extra pounds on top of the 110 pounds she can handle previously, so she can now lift 110+22 = 132 pounds. The answer is confirmed.

7 0
2 years ago
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If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH
olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

\angle EFG=\angle EFH+\angle HFG

18x+11=(5x+1)+(62)

18x+11=5x+63

Isolate variable terms.

18x-5x=63-11

13x=52

Divide both sides by 13.

x=\dfrac{52}{13}

x=4

The value of x is 4.

\angle EFH=(5x+1)^\circ

\angle EFH=(5(4)+1)^\circ

\angle EFH=(20+1)^\circ

\angle EFH=21^\circ

Therefore, the measure of ∠EFH is 21°.

8 0
3 years ago
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