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SSSSS [86.1K]
3 years ago
5

A. Quadrilateral ABCD is translated to the left 2 units and up 6 units. Write the translation in terms of x and y using

Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Step-by-step explanation:

Go up that much and create a shape

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B350m%7D%7B1s%7D" id="TexFormula1" title="\frac{350m}{1s}" alt="\frac{350m}{1s}" alig
cupoosta [38]

Answer:

ummmmmmmmmm this makes no sense

Step-by-step explanation:

4 0
3 years ago
The sum of three consecutive integers is 189. What are the integers?
Leto [7]

Answer: 62+63+64

Step-by-step explanation:

Divide 189 by 2. That gives you 63. Then go for a number 1 above it and 1 below it.

8 0
3 years ago
Review
Ahat [919]

Answer:  \bold{a)\quad 51, 54, 57\qquad a_n=a_{n-1}+3}

               \bold{b)\quad 250, 625, 1562.5\qquad a_n=(2.5)a_{n-1}}

<u>Step-by-step explanation:</u>

a) This is an arithmetic sequence where 3 is added to the previous term.

48 + 3 = 51

              51 + 3 = 54

                            54 + 3 = 57

The recursive formula for this sequence is:  a_n = a_{n-1}+3

*****************************************************************************************

b) This is a geometric sequence where 2.5 is multiplied to the previous term.

100(2.5) = 250

                250 (2.5) = 625

                                    625(2.5) = 1562.5

The recursive formula for this sequence is: a_n=(2.5)a_{n-1}

5 0
3 years ago
Someone please help me with this and show work I don’t get it I’ll give brainliest
kenny6666 [7]

Answer: THAT IS RIGHT OK BYE MAN

Step-by-step explanation: OK BYE

4 0
3 years ago
Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.
melomori [17]
V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C
</span>
4 0
4 years ago
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