All categories

3 years ago

4 pts What is the equation of the line parallel to y=3x+6 that contains the point (3,9)?

Mathematics

1 answer:

Levart [38]3 years ago

8 0

y=3x

Step-by-step explanation:

Lines that are parallel have the same slope. So we are looking for an equation with the same slope of 3x.

Since we have this information, we can plug in the numbers & solve

y=mx+b

9=3(3)+b

9=9+b

0=b

so the equation would be y=3x

You might be interested in

Is this right or wrong? Put these numbers in order from the smallest to the biggest. -1/5, -2/3, 2, 4.

quester [9]

Answer:no the -2/3 should be before -1/5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Lindsey bought supplies for a class project and brought the receipt to school. The 6 items cost:

DochEvi [55]

Answer:

Step-by-step explanation:

$5 appeared more in the prices

5 0

2 years ago

Read 2 more answers

6 percent of what number is 2

ycow [4]

The answer is 33.3 repeating

5 0

3 years ago

How can you identify unit rate from a table, equation and graph

Zina [86]

Answer:

hiiii

Step-by-step explanation:

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate.

(Table)

In a unit rate, the denominator is always 1. So, to find unit rate, divide the denominator with the numerator in a way that the denominator becomes 1. For example, if 50km is covered in 5.5 hours, the unit rate will be 50km/5.5 hours = 9.09 km/hour. ( equation)

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate. ( Graph)

8 0

3 years ago

A new car was valued at $28,000, and it's value depreciated to $14,000 over the next 3 years. Use the exponential equation for d

kompoz [17]

The exponential equation (in thousands) is:
$V = 28 e^{-rt}$
plug in t=3 yrs, and solve for 'r'.
$14 = 28 e^{-3r} \\ \\ \frac{1}{2} = e^{-3r} \\ \\ ln(\frac{1}{2}) = -3r \\ \\ r = \frac{ln(\frac{1}{2})}{-3} = 0.231 = 23.1%$

Find value of car when t = 10
$V = 28e^{-2.31} = 2.779$

8 0

3 years ago