Question

In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.

Answer 1

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

$BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}$