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Alex777 [14]
2 years ago
5

In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.

Mathematics
1 answer:
Inga [223]2 years ago
5 0

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}

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Option A

Step-by-step explanation:

Given expression:

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<u>Option A</u>

⇒ (x - 4)(3x + 2)

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<u>Option B</u>

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<u>Option C</u>

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⇒ (3x - 2)(x - 4)

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⇒ 3x² - 14x + 8

3x² - 10x - 8 = 3x² - 14x + 8 (No!)

Since the expression of option A has the same value as the given expression, option A is correct.

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