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lys-0071 [83]
3 years ago
14

For a hypothesis test of H0: p = 0.65 against the alternative Ha: p < 0.65, the z test statistic is found to be -2.35. What c

an be said about his finding?
The finding is significant at both α = 0.05 and α = 0.01.

The finding is significant at α = 0.05, but not at α = 0.01.

The finding is significant at α = 0.01, but not at α = 0.05.

The finding is not significant at α = 0.05 and α = 0.01.

The finding is inconclusive because we don't know the value of p
Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

The finding is significant at both α = 0.05 and α = 0.01.

Step-by-step explanation:

Given that:

Null hypothesis : H0: p = 0.65 against the Alternative Ha: p < 0.65,

The test statistic ; z test = - 2.35

From the test statistic value, we can obtain the p value of the test :

To determine if the claim is significant at both α = 0.05 and α = 0.01

We compare the Zstatistic and Zcritical values

If Zstatistic < Zcritical ; then we reject H0; if otherwise, we fail to reject H0

Zcritical at 95% one tailed = - 1.645 (left tail)

Zcritical at 95% one tailed = -2.326 (left tail)

- 2.35 < - 1.645

-2. 35 < 2.326

Since, Zstatistic < Zcritical;

The finding is significant at both α = 0.05 and α = 0.01.

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The patient is recommended to take 24 ounces of coffee per day.

<u>Step-by-step explanation:</u>

Patient normal intake of coffee daily = 5 times 12 ounces

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Doctor recommends to cut off 60 % of the normal intake of coffee.

And advised to take only 40 % of the daily intake of coffee.

So 60 % of 60 ounces can be calculated as,

$\frac{60 \times 60}{100}= 36 ounces

40 % of 60 ounces is 24 ounces.

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