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erma4kov [3.2K]
3 years ago
8

Which table represents a linear function?

Mathematics
1 answer:
taurus [48]3 years ago
4 0

Answer:

The table on the left

Step-by-step explanation:

Since it is a linear function the y value needs to increase in a constant change as the x value increases.

the table on the left the x value increases and the Y value increases by 1/2

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(Please help!!)<br> Find -5A + 4B
Natalija [7]

Answer:

I think it 7 ok ok ok ok ok ok

7 0
2 years ago
Suppose that a customer service center claims that the telephone calls it receives last 112 seconds on average, with a standard
adoni [48]

Answer:

95% Confidence interval:  (111.02,112.98)

Step-by-step explanation:

Average = 112 seconds

Standard Deviation = 9 seconds

n = 324

Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

112 \pm 1.96(\frac{9}{\sqrt{324}} ) = 112 \pm 0.98 = (111.02,112.98)

5 0
3 years ago
Write the formula to find the profit %, if selling price and cost price both are given.
jolli1 [7]

Answer:

profit \: percent =  \frac{sp - cp}{cp}  \times 100 \: percent

where,

SP=Selling price

CP=Cost price

<h3>For example:</h3>

Given,

Selling price(SP)= 1000

Cost price(CP)=800

Now,

profit \: percent =  \frac{sp - cp}{cp}  \times 100 \: percent \\  =  \frac{1000 - 800}{800}  \times 100 \\  =  \frac{200}{800}  \times 100 \\  = 25 \: percent

Hope this helps...

Good luck on your assignment..

5 0
2 years ago
Combine the following fractions by addition or subtraction as directed.
Marina86 [1]
Answer:\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}

Explanation:

Combining the fractions, we have:

\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\  \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\  \\ =\frac{-6(x+y)}{xy(x-y)} \\  \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}

8 0
1 year ago
According to the U.S. National Transportation Safety Board, the number of airline accidents by year from 1983 to 2006 were 23, 1
Lera25 [3.4K]

Answer:

\bar X= 33.79167

s= 12.06497

SE= \frac{s}{\sqrt{n}}= \frac{12.06497}{\sqrt{24}}=2.463

Median= \frac{30+31}{2}= 30.5

Step-by-step explanation:

For this case we have the following data:

23, 16, 21, 24, 34, 30, 28, 24, 26, 18, 23, 23, 36, 37, 49, 50, 51, 56, 46, 41, 54, 30, 40, and 31

We can calculate the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= 33.79167

Then we can calculate the standard deviation with this formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 12.06497

And the sample size for this case is n =24. We can calculate the standard error with this formula:

SE= \frac{s}{\sqrt{n}}= \frac{12.06497}{\sqrt{24}}=2.463

And the median for this case since the sample size is 24 first we need to sort the data on increasing order and we got:

16 18 21 23 23 23 24 24 26 28 30 30 31 34 36 37 40  41 46 49 50 51 54 56

And for this case the median would be the average from the position 12 and 13 and we got:

Median= \frac{30+31}{2}= 30.5

4 0
3 years ago
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