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Sauron [17]
3 years ago
12

If (3, y) lies on the graph of y = -(2^x) then y= 1/8 -6 -8

Mathematics
2 answers:
vazorg [7]3 years ago
8 0
<h3>Answer is   -8</h3>

Work Shown:

y = -(2^x)

y = -(2^3) ... replace x with 3

y = -(2*2*2) ... expand out 2 cubed

y = -8

GalinKa [24]3 years ago
6 0
I’m pretty sure the answer is -8
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2 years ago
Write the point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8. include all your
Juli2301 [7.4K]

<u>Answer: </u>

The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0

<u>Solution: </u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and parallel to the line with slope “m” is given as  

y-y_{1}=m\left(x-x_{1}\right) --- eqn 1

Where “m” is the slope of the line.  

x_{1} \text { and } y_{1} are the points that passes through the line.

From question, given that slope “m” = -8

Given that the line passes through the points (-8,2).Hence we get

x_{1}=-8 ; y_{1}=2

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.

y-2=-8(x-(-8))

On simplifying we get

y – 2 = -8(x +8)

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y – 2 +8x +64 = 0

8x + y +62 = 0

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7 0
2 years ago
Identify all of the real roots of x^4 − x^3 − 9x^2 + 11x + 6 = 0.
Norma-Jean [14]

Answer:

4 roots: 2 , -3, 1+√2, 1 - √2

Step-by-step explanation:

x⁴ − x³ − 9x² + 11x + 6 = 0    leading: 1 (x⁴)    Trailing: 6 (1,2,3,6)

possible roots: trailing/leading (±1 , ±2, ±3, ±6)

Test: x = 2     (2)⁴ - (2)³ - 9*(2)² + 11*(2) + 6 = 0

        x = -3    (-3)⁴ - (-3)³ - 9*(-3)² + 11*(-3) + 6 = 0

By rational roots test: possible roots (x-2)(x+3) are factors

Long division:  (x⁴ − x³ − 9x² + 11x + 6) / (x-2)(x+3) = x²-2x-1

roots of x²-2x-1: x= (-b±√b²-4ac) / 2a

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3 0
3 years ago
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