Basically any two numbers whose product is 44^2 = 1936.
so 16×121 = 1936
so the pair is 16 and 121
Answer:
x=7 and m<LMN = 120
Step-by-step explanation:
if MO bisects LMN then 13x - 31 must be equal to x + 53
13x - x = 53 + 31
12x = 84
x = 7
and
13x - 31 + x + 53 = m<LMN
14x + 22 = m<LMN
since x is 7
14×7 + 22 = 120
Answer:
does not terminate
Step-by-step explanation:
Answer:
explain further or send a picture of what you mean and then I can help you
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
