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Karo-lina-s [1.5K]
3 years ago
12

Please please please help me on this i'll give 14 points to whoever answers

Mathematics
1 answer:
Alexus [3.1K]3 years ago
4 0
Bro the answer is 600cm2
75% sure
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the length of a rectangle is 7 yd less than three times the width, and the area of the rectangle is 66 yd(squared). find the dim
Alex_Xolod [135]
So legnt=l
width=w
l=-7+3w
l=3w-7

area=66
area=legnth times width or
area=lw

subisutte
area=lw
l=3w-7
66=(3w-7)(w)
66=3w^2-7w
subtrac 66 from both sides
0=3w^2-7w-66
factor
HOW TO
multiply 3 and -66=-198
find what 2 numbers add up to -7 and multiply to get -198
the numbers area 11 and -18
so
3w^2-18w+11w-66=0
factor
(3w^2-18w)+(11w-66)=0
(3w)(w-6)+(11)(w-6)=0
factor using distributive (ab+ac=a(b+c))

(3w+11)(w-6)=0
set them to zero
3w+11=0
subtract 11
3w=-11
legnths cannot be negative so we discard this

w-6=0
add 6
w=6

width=6
legnth=3w-7
length=3(6)-7
legnt=18-7
legnth=11


width=6
legnth=11

7 0
3 years ago
Do the table and the equation represent the same function ? Y=390+11(x)
Furkat [3]

<u>Answer:</u>

No

<u>Step-by-step explanation:</u>

We are given the following equation of a function and a table for the corresponding values of this function:

y=390+11(x)

We are to determine if the equation and the table represent the same function.

To check that, we will substitute the value of x in the equation to see if it gives the same values of y as in the table.

y=390+11(-30) ---> (-30, 60)

y=390+11(-28) ---> (-28, 82)

y=390+11(-26) ---> )-26, 104)

Since these paired values differ from the ones given in the table. Therefore, table and equation do not represent the same function.

8 0
4 years ago
What is the solution to 2 log Subscript 9 Baseline (x) = log Subscript 9 Baseline 8 + log Subscript 9 Baseline (x minus 2) x = n
Kaylis [27]

Answer:

\large\boxed{\large\boxed{x=4}}

Step-by-step explanation:

The equation to solve is:

            2\log_9 x=\log_9 8+\log_9 (x-2)

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"

Thus, the left-hand side is:

               2\log_9 x=\log_9 x^2

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":

Then, on the right-hand side:

        \log_9 8+\log_9 (x-2)=\log_9 8(x-2)

3. <u>Make them equal</u>:

      \log_9 x^2=\log_9 8(x-2)

4. Since the two functions are the same, <u>make the arguments equal</u>:

     x^2=8(x-2)

5. <u>Solve the equation</u>:

        x^2=8x-16\\\\x^2-8x+16=0\\\\(x-4)^2=0\\\\x-4=0\\\\x=4\leftarrow solution

4 0
3 years ago
Read 2 more answers
The area of cross section of the large piston in a hydraulic machine is 1m² and that of small piston is 0.5m².calculate the forc
Dvinal [7]

Answer:

The force that must be applied on the small piston has a magnitude of 500 newtons.

Step-by-step explanation:

By Pascal's Principle, we know that pressure within any point of a closed hydraulic system is the same. Hence, the hydraulic machine can be described by the following model:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Where:

F_{1}, F_{2} - Forces applied on the small and large pistons, in newtons.

A_{1}, A_{2} - Areas of the small and large pistons, in square meters.

If we know that A_{1} = 0.5\,m^{2}, A_{2} = 1\,m^{2} and F_{2} = 1000\,N, then the force to be applied on the small piston is:

F_{1} = \left(\frac{A_{1}}{A_{2}} \right)\cdot F_{2}

F_{1} = \left(\frac{0.5\,m^{2}}{1\,m^{2}} \right)\cdot (1000\,N)

F_{1} = 500\,N

The force that must be applied on the small piston has a magnitude of 500 newtons.

4 0
3 years ago
Which unit rate is the lowest price per ounce? (1 point) ) Choice A: 25 ounces of potato chips for $3.49 Choice B: 40 ounces of
kirill [66]

Answer:

R$0,00

Step-by-step explanation:

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3 0
3 years ago
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