So legnt=l
width=w
l=-7+3w
l=3w-7
area=66
area=legnth times width or
area=lw
subisutte
area=lw
l=3w-7
66=(3w-7)(w)
66=3w^2-7w
subtrac 66 from both sides
0=3w^2-7w-66
factor
HOW TO
multiply 3 and -66=-198
find what 2 numbers add up to -7 and multiply to get -198
the numbers area 11 and -18
so
3w^2-18w+11w-66=0
factor
(3w^2-18w)+(11w-66)=0
(3w)(w-6)+(11)(w-6)=0
factor using distributive (ab+ac=a(b+c))
(3w+11)(w-6)=0
set them to zero
3w+11=0
subtract 11
3w=-11
legnths cannot be negative so we discard this
w-6=0
add 6
w=6
width=6
legnth=3w-7
length=3(6)-7
legnt=18-7
legnth=11
width=6
legnth=11
<u>Answer:</u>
No
<u>Step-by-step explanation:</u>
We are given the following equation of a function and a table for the corresponding values of this function:

We are to determine if the equation and the table represent the same function.
To check that, we will substitute the value of x in the equation to see if it gives the same values of y as in the table.
---> (-30, 60)
---> (-28, 82)
---> )-26, 104)
Since these paired values differ from the ones given in the table. Therefore, table and equation do not represent the same function.
Answer:

Step-by-step explanation:
The equation to solve is:

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"
Thus, the left-hand side is:

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":
Then, on the right-hand side:

3. <u>Make them equal</u>:

4. Since the two functions are the same, <u>make the arguments equal</u>:

5. <u>Solve the equation</u>:

Answer:
The force that must be applied on the small piston has a magnitude of 500 newtons.
Step-by-step explanation:
By Pascal's Principle, we know that pressure within any point of a closed hydraulic system is the same. Hence, the hydraulic machine can be described by the following model:
(1)
Where:
- Forces applied on the small and large pistons, in newtons.
- Areas of the small and large pistons, in square meters.
If we know that
,
and
, then the force to be applied on the small piston is:



The force that must be applied on the small piston has a magnitude of 500 newtons.
Answer:
R$0,00
Step-by-step explanation:
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