Ask question

Ask question

All categories

2 years ago

10

Joy has an evenly divided spinner with one of the letters A through E in each section. She also has a number cube with one of th

e numbers 1 through 6 on each side
E AA
D B
What is the probability of rolling a 5 and spinning a B?
11
30
1
11
5
6
1
30

1 answer:

Anton [14]2 years ago

6 0

Answer: 1/30

Step-by-step explanation:

You might be interested in

Jeffrey set up chairs for a meeting.

Kazeer [188]

Answer:

9x + 3 = 7x + 19

Step-by-step explanation:

Given that,

Jeffrey set up chairs for a meeting.

He arranged the chairs in 9 equal rows but had 3 chairs left over.

Let x be the number of chairs. So,

9x+3 .....(1)

Then he arranged the chairs in 7 equal rows but had 19 chairs left over. So,

7x+19 ......(2)

From equation (1) and (2),

9x+3 = 7x+19

9x-7x = 19-3

2x = 16

x = 8

Hence, the correct option is (b).

3 0

2 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

F. one die is rolled 3 times. what is the chance of getting no 2's?

aniked [119]

6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions

6 0

2 years ago

Please help will give brainlist

adoni [48]

Answer:

It would be option 2.

Step-by-step explanation:

This is because option 1 does not have a irrational number that goes on indefinitely, option three has the square root of 25, which equals 5 meaning it is rational, and the last option also gives us rational choices. Therefore, the only possibility is that it would be option 2.

6 0

2 years ago

Read 2 more answers

crimeas [40]

Answer:

Concept: Mathematical Analysis

2 friends share 56
5- 10 dollar bills and 6- one dollar
We split the bills in half to equate equal change.
Hence 5 bills ÷2= 2.5 or 25 dollars
6 bills÷2= 3 or 3 dollars
You need to make change for the 10 dollars, break a bill into 5's

3 0

2 years ago