3. The trapezoid below contains a square and two right triangles. Find the perimeter of the trapezoid.
1 answer:
Answer:
Perimeter of trapezoid = 25.66 cm
Step-by-step explanation:
Trapezoid ABCD contains two triangles ΔABF, ΔCDE and a square with side length 4 cm.
By applying Pythagoras theorem in ΔABF,
AB² = BF² + AF²
AB² = 4² + 3²
AB =
AB = 5 cm
Similarly, By applying Pythagoras theorem in ΔCDE,
CD² = DE² + CE²
CD² = 4² + 4²
CD =
CD =5.66 cm
Perimeter of the given trapezoid = AB + BC + CD + AD
= 5 + 4 + 5.66 + (3 + 4 + 4)
= 25.66 cm
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Answer:
Height = 5 and Base = 10
Step-by-step explanation:
The base of the parallelogram is twice the perpendicular height of the parallelogram. The area of the parallelogram is 50 cm².
Formula for area of parallelogram = base × height
Base = 2h
Height = h
∴ Area = 2h × h = 50
Solution:
2h × h = 50
2h² = 50
h² = 25
h = 5
∴ height = 5 and base = 2(5) = 10