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Softa [21]
3 years ago
7

ΔABC ​~ ΔDEC. ∠1 and ∠2 have the same measure. Find DC and DE.​ (Hint: Let DC=x and AC=x+3. Use the figure shown.)

Mathematics
1 answer:
Sveta_85 [38]3 years ago
8 0
DC/AC=EC/BC
x/(x+3)=10/16
10(x+3)=16x
10x+30=16x
30=6x
x=5
DC=x=5
DC=5 units long

10/16=DE/AB,     DE=y

10/16=y/10
16*y=10*10
y=6.25≈6.3
DE≈6.3

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
4 years ago
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Novay_Z [31]

Answer:

3/8 was the swimming segment!

Step-by-step explanation:

We only need to subtract the bike and running segment from the total distance:

15 11/16 - 12 1/4 - 3 1/16

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5 0
3 years ago
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Answer:

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