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3 years ago

3(x+6)= -3.68 Find x, I think I know how but I’m not really sure

Mathematics

1 answer:

Wittaler [7]3 years ago

8 0

Answer:

x = - 7.23

Step-by-step explanation:

3(x+6)= -3.68 Start with the breackets.

3x + 18 = - 3.69 Subtract 18 from both sides

3x = - 3.69 - 18

3x = -21.69 Divide by 3

x = - 21.69/3

x = -7.23

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A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su

zaharov [31]

Answer:

After 1st year, the age distribution will be

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

$A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]$

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

$x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

$x_1 = A \cdot x$

$x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]$

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

$x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

After 2nd year, the age distribution will be

$x_2 = A \cdot x_1$

$x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]$

$x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]$

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4 years ago

Ben is monitoring a colony of bacteria. Initially, the colony consists of 159 bacteria. The following function represents the nu

padilas [110]

Answer:

No solution is possible from the information provided

Step-by-step explanation:

you didn't include the function.

7 0

3 years ago

Need help an is due monday please show your work please please

AysviL [449]

G represents 3/6 ......

4 0

3 years ago

Create a two column proof for each question. Please help!!

jonny [76]

Answer:

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8 0

3 years ago

Use the identity below to complete the tasks:

quester [9]

Answer:

$a=[2q^{2}r]$

$b=[3s^{2}t]$

Step-by-step explanation:

we have

$8q^{6}r^{3}+27s^{6}t^{3}$

we know that

$8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}$

$27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}$

therefore

$a=[2q^{2}r]$

$b=[3s^{2}t]$

substitute

$a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])$

7 0

3 years ago

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