Answer:
The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.
Step-by-step explanation:
We have these following rates of type II diabetes:
7% among Caucasians
10% among African-Americans
12% among Hispanics
5% among Asian-Americans.
The ethnic distribution of Houston is:
30% Caucasian
25% African-American
40% Hispanic
5% Asian-American
What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?
is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.
is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.
is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.
is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.
The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.
8 is the answer, because 4 x 8 = 32
Answer:
104x + 52
None of the expressions listed are equivalent to 52(2x + 1)
Step-by-step explanation:
52(2x + 1)
Apply the distributive law: a(b + c) = ab + ac
⇒ 104x + 52
Therefore, 52(2x + 1) = 104x + 52
Answer:
Step-by-step explanation:
a) No of outcomes= 7
total no of outcomes= 10
probability = no of outcomes/total no of outcomes
=7/10
b) 4/10 ( since the outcomes could be 1,2,3,4)
c) no 1 to 10 has 5 odd numbers
so, probability = 5/10 = 1/2
d) multiples of 3 from 1 to 10 are :-
3,6,9= 3 no's
so probability = 3/10
Answer:
196
Step-by-step explanation:
13 plus 1 is 14 then multiply 14 by itself twice
