Four consecutive integers... n, n+1, n+2, n+3.
The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.
n(n+3)=2n(n+3)-4 perform indicated multiplications...
n^2+3n=2n^2+6n-4 subtract n^2 from both sides
3n=n^2+6n-4 subtract 3n from both sides
n^2+3n-4=0 factor
n^2-n+4n-4=0
n(n-1)+4(n-1)=0
(n+4)(n-1)=0, and since n>0
n=1
So the four numbers are 1, 2, 3, 4
check...
1(4)=2(1)4-4
4=8-4
4=4
Answer:
The above result is proved with the help of Pythagoras theorem and explained below.
Step-by-step explanation:
Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.
In triangle ADC,
By applying Pythagoras theorem, we get
→ (1)
In triangle ABC,
→ (2)
Now, from eq (1) and (2)
Peach Tree Dr. is the same distance as Sycamore Ln.
⇒
(∵ AD=BC)
⇒ DC=AB (∵Distance can never negative)
Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.
Answer:
I think the answer is 44.13
Step-by-step explanation:
sorry if I am wrong
we have that
x + 3y = 6 -------> first equation
2x − y = 10
x + 3y = 6-----> substract x both sides
-x+x+3y=6-x
3y=6-x-----> divide by 3 both sides
y=(6-x) /3
y=2-(x/3)
y=-(x/3)+2
therefore
the answer is
negative one thirdx + 2
Answer:
lots of multiplying I've noticed