Which is the correct algebraic representation for the area of a circle?

Mathematics

1 answer:

fiasKO [112]2 years ago

4 0

B because pie radius square = area of a circle

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You ask your friend which U.S. states have the greatest population densities. Your friend says it must be California and Texas b

Brilliant_brown [7]

"-No, because California and Texas also have two of the greatest areas, so they may not have the greatest population densities."

This is correct as the states such as New Jersey may not have as large as a population as Texas and California but, have a significantly less land than those states. Population density refers to people per km squared, which takes both land and population into account.

Hope this helps!
-Benjamin

6 0

2 years ago

6+7=10 13+8=18 32+21=32 11+34=0 31+03=? process please

Stella [2.4K]

Answer:

6+7=13

13+8=21

32+21=52

11+34=46

31+03=34

Step-by-step explanation:

im not sure in the 31+03

4 0

2 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$