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dimulka [17.4K]
4 years ago
14

Which expression represents "2 less than the product of 5 and a number"?

Mathematics
2 answers:
diamong [38]4 years ago
7 0
Two less ( means minus 2) the product of (means multiply) 5 and a number.   
so you get (5n) -2
USPshnik [31]4 years ago
4 0

Answer:

it can also just be 5n-2 without ( )

Step-by-step explanation:

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40•(420:x-37)=200 помогите решить уравнение
miv72 [106K]
40•(420:x-37)=200 <span>означает 40(\frac{420}{x}-37)=200
</span>
<span>разделите обе стороны на 40
</span><span>
\frac{420}{x}-37=5
</span>
<span>добавить 37 с обеих сторон

\frac{420}{x}=42
</span>
<span>умножить обе стороны на х
420=42x

</span><span>разделите обе стороны на 42
10=x
x=10
</span>
4 0
3 years ago
Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

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