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Anarel [89]
3 years ago
5

The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width

Mathematics
1 answer:
Elza [17]3 years ago
4 0

P = perimeter

Perimeter of a rectangle = l + l + w + w

or  P = 2l + 2w

You know:

P = 150 m

l = w + 5     [length is 5 m greater than the width]

P = 2l + 2w        Plug in what you know

150 = 2(w + 5) + 2w     Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10     Subtract 10 to both sides of the equation

140 = 4w       Divide 4 on both sides

35 = w

PROOF               l = w + 5 --->  l = 40

P = 2l + 2w

150 = 2(40) + 2(35)

150 = 80 + 70

150 = 150

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We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

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