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3 years ago

The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width

Mathematics

1 answer:

Elza [17]3 years ago

4 0

P = perimeter

Perimeter of a rectangle = l + l + w + w

or P = 2l + 2w

You know:

P = 150 m

l = w + 5 [length is 5 m greater than the width]

P = 2l + 2w Plug in what you know

150 = 2(w + 5) + 2w Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10 Subtract 10 to both sides of the equation

140 = 4w Divide 4 on both sides

35 = w

PROOF l = w + 5 ---> l = 40

P = 2l + 2w

150 = 2(40) + 2(35)

150 = 80 + 70

150 = 150

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Answer:

1. B

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Step-by-step explanation:

** Attached picture of the situation

The bird caught the fish at point A, flew until B (which is 100 yds away, dropped the fish at C (which is horizontally 50 yards from A).

We want the angle that the bird creates with the water (horizontal). It is angle BAC. With respect to the right triangle, we can say that we know "hypotenuse" and "adjacent" side to angle BAC. cosine relates hypotenuse and adjacent, thus we can write:

$Cos(BAC)=\frac{50}{100}\\Cos(BAC)=\frac{1}{2}\\BAC=Cos^{-1}(\frac{1}{2})\\BAC=60$

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4 0

3 years ago

Read 2 more answers

A road is 8/9 of a mile long. A crew needs to repave 2/5 of the road. How long is the section that needs to be repaved?

Rama09 [41]

Answer:

16/45

Step-by-step explanation:

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2 years ago

Challenge Yael used to have a square garage with 370 ft ^2of floor space. She recently built an

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Scale factor of area is the square of the scale factor of length

The required values are;

The length of one sides of the garage was originally approximately 19.2 ft.

The length of one of the sides of the garage is now approximately 23.6 feet long

The percentage increase in length is approximately 22.5 %

Reason:

The given parameters are;

The area of the square garage = 370 ft.²

The area of the new garage has 50% more space

Required;

Part A

The initial side length

The initial side length, given to the nearest tenth, s, is the square root of the area, A, given as follows;

s = √(370 ft.²) ≈ 19.2 ft.

Part B

The side was increased by 50%, to give,

370 + 0.5×370 = 555

The new area of the garage = 555 ft.²

The side length of the new garage, s = √(555) ≈ 23.6

The side of the garage now is 23.6 ft.

Part C

The percentage increase is given as follows;

$The \ percentage \ increase \ in \ length = \dfrac{New \ length - Initial \ length}{Initial \ length }$

$The \ percentage \ increase \ in \ length = \dfrac{\sqrt{555} - \sqrt{370} }{\sqrt{370} } \times 100 \approx 22.5 \%$

The percentage increase in length of the side of the garage is approximately 22.5 %

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2 years ago

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Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

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3 years ago

Question 18

kobusy [5.1K]

Answer:

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Step-by-step explanation:

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2 years ago