8y^2 + 12x - 4y^2 + 24x
= 4y^2 + 36x
Answer:
The graph of g is the graph of f shifted down 1 unit.
Step-by-step explanation:
Suppose you have a function y = f(x), you can do these following operations on the function:
Shift up a units: y = f(x) + a
Shift down a units: y = f(x) - a
Shift left a units: y = f(x + a)
Shift right a units: y = f(x - a)
In this problem, we have that:
g(x) = -1 + f(x) = f(x) - 1
So the graph of g is the graph of f shifted down 1 unit.
Answer:
-1
Step-by-step explanation:
Let the points be <u>(0, a)</u> and <u>(a, 0)</u> (As it mentions the intercepts are equal)
==============================================================
Applying slope formula :
⇒ m = 0 - a / a - 0
⇒ m = -a/a
⇒ <u>m = -1</u>
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is:
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore, 2⁵⁰ binary strings of length 50 are there and so it would require:
log₂(2⁵⁰) <span>= 50 bits.
b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:
log2(109)= 29.89
<span> = 30 bits. (rounded to the nearest whole #)
c). </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
log₂(10,4)=log₂(210) = 7.7
= 8 bits. (rounded to the nearest whole #)
