Answer:
y=-1/4x-6
Step-by-step explanation:
y intercept is -6 and slope is -1/4
point slope is y-y1=m(x-x1)
you can use and point. i am using (0,-6)
y--6=-1/4(x-0)
y+6=-1/4x
-6 -6
y=-1/4x-6
Answer: 918km^2
Step-by-step explanation:
Let x be the new dimension of the area;
Answer:
f(-2) = 11
Step-by-step explanation:
Hello!
We can evaluate y by plugging in -2 for x in the equation.
<h3>Evaluate</h3>
- f(x) = 8|x| - 5
- f(-2) = 8|-2| - 5
- f(-2) = 8(2) - 5 Remember that absolute value turns the number positive
- f(-2) = 16 - 5
- f(-2) = 11
The evaluated value is 11.
5(-4)+22 = (-4)+6
-20+22 = -4+6
2 = 2
Maria is correct, since both sides equally match.
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
