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Shalnov [3]
3 years ago
6

Five over seven plus blank over six equals fifty one over forty two

Mathematics
1 answer:
NISA [10]3 years ago
6 0

Answer:

The blank is 3

Step-by-step explanation:

1 - Give the blank a variable

x = our blank

2 - Write it out

\frac{5}{7} + \frac{x}{6} = \frac{51}{42}

3 - Get the denominators equal

\frac{5}{7}(\frac{6}{6}) +\frac{x}{6}(\frac{7}{7}) = \frac{51}{42} \\\frac{30}{42}+\frac{7x}{42} = \frac{51}{42}

4 - Simplify

\frac{30+7x}{42} = \frac{51}{42} \\ \frac{30+7x}{42} = \frac{51}{42}

5 - Solve for the numerators

30+7x = 51

-30         -30

      7x = 21

        x = 3

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How do you solve for x in a math question like this 5+4x=54-3x?
Bas_tet [7]

To solve for x, first you need to isolate all x terms on the same side so:

you start with 5 + 4x = 54 - 3x

subtract 5 from both sides to get 5 onto the left side

now you should have 4x = 49 - 3x

now add 3x to both sides to get 3x onto the right side

now you should have 7x = 49

now that you have your x on one side you can solve this like a regular one step equation and divide both sides by 7

this leads you to your answer of x = 7

hope this helps!

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3 years ago
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a quarter fell out of james’ pocket each day for a week. what integer represents how much money james lost over the course of th
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Quarter =25 cents
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3 0
3 years ago
What is the missing number? 0, 1, 1, 2, 3, 5, 8, ___, 21, 34?
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It is a <span>Fibonacci Sequence:

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8 0
3 years ago
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A car is traveling at a speed of 55 miles per hour.you want to write an algebraic expression to show how far the car will travel
goblinko [34]
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4 0
3 years ago
Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp
romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

\text{Distance}=\text{Speed}\times \text{Time}

\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}

\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}.

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}

\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

\text{Distance between both cars}=\sqrt{147^2+150^2}

\text{Distance between both cars}=\sqrt{21609+22500}

\text{Distance between both cars}=\sqrt{44109}

\text{Distance between both cars}=210.021427\approx 210

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0
3 years ago
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