Most researchers suggest that it should range from 10% to 15% (15 percent as the max) to be allocated for food from your net spendable income.
Answer:
(a) 0.76
(b) 0.46
(c) 0.58
Step-by-step explanation:
Let's first list the probabilities of each event:
Buyers using online search engine: 0.65
Buyers skipping test drive = 0.11
Buyers that use search engines AND skip test drives = 0.65 * 0.11 = 0.07
(a) To find this probability, we simply need to add the probabilities of the above conditions that meet the criteria of the question. Since all of the above conditions meet the criteria set by the question, we have:
Probability = 0.65 + 0.11
Probability = 0.76
(b) The probability of buyers that do not use search engines = 1 - 0.65 = 0.35
Probability of buyers that do not use search engines OR do skip the test drive = 0.35 + 0.11 = 0.46
(c) Probability of buyers buyers that do not skip test drive = 1 - 0.11 = 0.89
Probability of buyers using online search engine AND not skipping the test drive = 0.65 * 0.89 = 0.58
(It must be noted that question c is phrased wrong. Since both events are independent, i.e buying a car OR skipping the test drive would mean 0.65 + 0.89 = 1.54 (not possible) )
Answer:99.7
Step-by-step explanation:
-180 is the answer
explanation: order of operations
Answer: Answer:Median: 10.5Lower quartile: 4Upper quartile: 16Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 12 (even)Median = Mean of (6)th and (7)th observations = 10 + 11 divided by 2 = 21/2 = 10.5Therefore the median is 10.5.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 16Question 2.the lengths of 10 pencils, in centimeters:18, 15, 4, 9, 14, 17, 16, 6, 8, 10Type below:_________________Answer:Median: 12Lower quartile: 4Upper quartile: 18Explanation:Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 10 (even)Median = Mean of (5)th and (6)th observations = 10 + 14 divided by 2 = 24/2 = 12Therefore the median is 12.After writing in ascending or descending order the first and last terms justify the lower and upper limits respectively.They are:Lower quartile: 4Upper quartile: 18Question 3.Make a box plot to display the data set in Exercise 2.Type below:_________________Answer:The above box plot represents the lower and upper quartiles, the median.Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Question 4.The numbers of students on several teams are 9, 4, 5, 10, 11, 9, 8, and 6. Make a box plot for the data.Type below:_________________Answer: Explanation:Box plot is drawn using the number line and the rectangle which is drawn above it.The ends of the rectangles say about the lower and upper limits and the middle line indicates the median.Therefore the lower and upper quartiles are 4 and 11 respectively.Median:First, write the observations in ascending order or descending order.The formula to calculate the median is mean of (n/2) and (n/2+1)th observations, for even number of observationsn = 8 (even)Median = Mean of (4)th and (5)th observations = 8 + 9 divided by 2 = 17/2 = 8.5Therefore the median is 8.5.
Step-by-step explanation:
