Answer:
I’m lost
Step-by-step explanation:
Answer:
The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 45 - 1 = 44
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12.1 - 0.4 = 11.7 units
The upper end of the interval is the sample mean added to M. So it is 12.1 + 0.4 = 12.5 units
The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.
Answer:
C
Step-by-step explanation:
Since the polynomial is of 3rd degree, it has 3 solutions. The possibilities are 3 real solutions or 1 real solution and 2 imaginary solutions.
Therefore, C is the correct answer
Answer:
NEITHER I THINK
Step-by-step explanation:
Answer:
h(1.5) = 7.3 ft
h(10.3) = 24.9 ft
Step-by-step explanation:
Given the function h(d) = 2d + 4.3,
where:
h = height of the water in a fountain (in feet)
d = diameter of the pipe carrying the water (in inches)
<h3>h(1.5)</h3>
Substitute the input value of d = 1.5, into the function:
h(1.5) = 2(1.5) + 4.3
h(1.5) = 3 + 4.3
h(1.5) = 7 feet
The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.
<h3>h(10.3)</h3>
Substitute the input value of d = 10.3, into the function:
h(10.3) = 2(10.3) + 4.3
h(10.3) = 20.6 + 4.3
h(10.3) = 24.9 feet
The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.
<h3>Context of the solutions to h(1.5) and h(10.3):</h3>
The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain. The height of the water in fountain increases relative to the diameter of the pipe. In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.
