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ryzh [129]
3 years ago
8

Graph the line with the equation y=1/5x+4.

Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Step-by-step explanation:

I hope this helps you answer your question and sorry if its wrong.

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We have to choose 5 people to form a student government. We have to pick 5 people out of 7 girls and 5 boys.
qwelly [4]

Answer:

The probability of picking at least three boys is \frac{5}{41} .

Step-by-step explanation:

We have to choose 5 people to form a student government.

We have to pick 5 people out of 7 girls and 5 boys.

What is the probability that at least 3 boys are a part of the student government?

The probability of picking 5 people out of 12 girls and boys = \frac{5}{12}

The probability of picking at least 3 boys excludes the probability of picking 3 girls. The probability of picking 3 girls = \frac{3}{7}

The probability of picking at least 3 boys = 1 - \frac{3}{7} = \frac{2}{7}

The probability of picking 5 people and the probability of picking at least 3 boys = \frac{5}{12} × \frac{2}{7} = \frac{5}{41}

6 0
3 years ago
There are a total of 120 counters in a box.
Montano1993 [528]

Answer:

The ratio of red to blue would be 60: 6 which can be simplified to 10:1.

6 0
3 years ago
If the following system of equations was written as a matrix equation in the form AX = C,? and matrix A was expressed in the for
LenaWriter [7]
The given equations are
5x + 7y = 7
3x - 2y = 9

As a matrix equation,
A = [5   7
       3 -2]

X = [x
        y]

C = [7
       9]
That is
a =5, c=7; and b=3, d=-2

a - b + c + d = 5 - 3 + 7 + (-2) = 7

Answer: 7
4 0
3 years ago
Read 2 more answers
Answer the following questions. a. In the general education course requirement at a college, a student needs to choose one each
Bezzdna [24]

Answer:

a) N = 240 ways

b) N = 303,600 ways

c) N = 10 ways

Step-by-step explanation:

a) Given

General course consist of one course from each of 4 groups.

Social Science = 5 options

Humanities = 4 options

Natural sciences = 4 options

Foreign language = 3 options.

Therefore the total number of possible ways of selecting one each from each of the 4 groups is:

N = 5×4×4×3 = 240 ways

b) if four people are chosen from 25 member for four different positions, that makes it a permutation problem because order of selection is important.

N = nPr = n!/(n-r)!

n = 25 and r = 4

N = 25P4 = 25!/(25-4)! = 25!/21!

N = 303,600 ways

c) The number of ways by which 5 tosses of coin can yield 2 heads and 3 tails.

N = 5!/(5-5)!(2!)(3!)

N = 5×4/2

N = 10 ways

7 0
3 years ago
Log 15 (2x − 2) = log 15 (x+9)
notka56 [123]

Answer:

x=11

Step-by-step explanation:

Given the equation

\log_{15}(2x-2)=\log_{15}(x+9)

Note that

2x-2>0\\ \\2x>2\\ \\x>1

and

x+9>0\\ \\x>-9

Combined, x>1

Solve the equation:

2x-2= x+9\\ \\2x-x=9+2\\ \\x=11

Since 11>1, this is the solution to the equation.

5 0
4 years ago
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