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pav-90 [236]
3 years ago
11

Jimmy is selling used books at a yard sale. A customer buys 9 books at a cost of $0.75 each and pays with a $20.00 bill. Jimmy m

ust determine c, the amount of change in dollars he should give the customer. Which equation represents c?
A. 20 - 0.75c = 9
B. 20 - 0.75 = 9c
C. 0.75(9) + c = 20
D. 0.75c + 9 = 20
Mathematics
1 answer:
KatRina [158]3 years ago
7 0
C
Because .75 times 9 would give you the price of the books and then you would have to add C, the amount left to get to 20.
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Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
Zepler [3.9K]
<h2>Hello!</h2>

The answer is:

Ava and Kelly will be 3/4 mile apart after 0.375 hours.

<h2>Why?</h2>

To calculate when will Ava and Kelly be 3/4 mile apart, we need to write the equations for both Ava's and Kelly's positions.

Writing the equations we have:

For Ava:

x_A=x_o+v_ot\\\\x_A=0+v_o*t\\\\x_A=v_{o(ava)*t

For Kelly:

We need to calculate when Kelly will be 3/4 mile apart becase is running faster than Ava, so, writing the equation we have:

x_K=x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

Now, substituting the equation for Ava into the equation for Kelly, we have:

x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+\frac{3}{4}mile}=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+0.75mile}=x_{o}+v_{o(Kelly)}*t\\\\6mph*t+0.75mile=8mph*t\\\\0.75mile=2mph*t\\\\t=\frac{0.75miles}{2mph}=0.375hours

To prove  that the result is correct, we just need to substitute the obtained value for time into both equations, so, substutiting we have:

For Ava:

x_A=v_{o(ava)*t=6mph*0.375hours=2.25miles

For Kelly:

x_K=v_{o(Kelly)}*t=8mph*0.375=3miles

There is a difference of 0.75 miles or 3/4 mile between Ava and Kelly, so, the obtained value for time is correct.

Therefore, we have that Ava and Kelly will be 3/4 mile apart after 0.375 hours.

Have a nice day!

5 0
3 years ago
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