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maxonik [38]
3 years ago
9

Determine the given pair of lines of parallel, perpendicular, or intersecting.

Mathematics
1 answer:
podryga [215]3 years ago
8 0
k:\ y=m_1\cdot x+b_1\ \ \ \ and\ \ \ \ l:\ y=m_2\cdot x+b_2 \\\\k\ ||\ l\ \ \ \Leftrightarrow\ \ \ m_1=m_2\ \ \ \ \ \ and \ \ \ \ \ \ k\ \bot\ l\ \ \ \Leftrightarrow\ \ \ \ m_1\cdot m_2=-1\\----------------------------\\1.\\ k:\ y= \frac{7}{3} x-8\ \ \ and\ \ \ l:\ y=\frac{7}{3} x+3\\\\m_1=m_2=\frac{7}{3}\ \ \ \Rightarrow\ \ \ k\ ||\ l

2.\\k:\ y=2x-1\ \ and\ \  l:\ -x+2y=6\ \Rightarrow\ \ 2y=x+6\ \ \Rightarrow\ \ y= \frac{1}{2}x+3 \\\\m_1 \neq m_2\ \ \ and\ \ \ m_1\cdot m_2 \neq -1\ \ \ \Rightarrow\ \ \ the\ lines\ intersect\\\\3.\\k:\ y= \frac{5}{2} x-17\ \ \ and\ \ \ l:\ y=- \frac{5}{2} x-1\ \ \ \Rightarrow\ \ \ the\ lines\ intersect\\\\4.\\k:\ y= \frac{5}{2} x-4\ \ and\ \ l:\ -5x+2y=6\ \Rightarrow \ 2y=5x+6\ \Rightarrow \ y= \frac{5}{2}x +3\\\\m_1=m_2= \frac{5}{2} \ \ \ \Rightarrow\ \ \ k\ ||\ l

5.\\k:\ y=- \frac{2}{3} x+12\ \ \ and\ \ l:\ y= \frac{3}{2} x+3\\\\m_1\cdot m_2=- \frac{2}{3}\cdot \frac{3}{2} =-1\ \ \ \Rightarrow\ \ \ k\ ||\ l\\\\6.\\k:\ y= \frac{1}{3}x-13\ \ \ and\ \ \ l:\ y=3x+2\ \ \ \Rightarrow\ \ \ the\ lines\ intersect \\\\7.\\k:\ y=-4x+5\ \ ,\ \ l: -x+4y=-16\ \Rightarrow\ 4y=x-16\ \Rightarrow\ y= \frac{1}{4}x-4 \\\\m_1\cdot m_2=-4\cdot \frac{1}{4} =-1\ \ \ \Rightarrow\ \ \ k\ \bot\ l

8.\\k:\ y= \frac{2}{3} x+3 \ ,\ \ l:\ -2x+3y=21 \ \Rightarrow\ \ 3y=2x+21\ \Rightarrow\ y= \frac{2}{3} x+7\\\\m_1=m_2= \frac{2}{3} \ \ \ \Rightarrow\ \ \ k\ ||\ l
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20 equals 5 times negative 3 plus x
kotykmax [81]

Answer:

20=5*-3+x or 20=-15+x or 35=x

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HELPPPP PLSSSS IT'S UNIT RATE BUT I Don't HAVE MUCH TIME TO DO IT!!!​
horsena [70]

Answer:

So Jennys Jean store charges the higher rate.

Step-by-step explanation:

Jeanys Jean store

Cost/pair = 20/1 = $20 per pair

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So Jennys Jean store charges the higher rate.

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2 years ago
Please help helppp :((((
ella [17]

Answer:

m∠Q = 61°

m∠S = 61°

m∠R = 58°

Step-by-step explanation:

Since we have an isosceles triangle, we know that ∠Q and ∠S are congruent.

Step 1: Definition of isosceles triangle

2x + 41 = 3x + 31

41 = x + 31

x = 10

Step 2: Find m∠Q

m∠Q = 2(10) + 41

m∠Q = 20 + 41

m∠Q = 61°

Step 3: Find m∠S

Since m∠Q = m∠S,

m∠S = 61°

Step 4: Find m∠R (Definition of a triangle)

Sum of angles in a triangle adds up to 180°

m∠R = 180 - (61 + 61)

m∠R = 180 - 122

m∠R = 58°

4 0
3 years ago
Find the product.<br> 5x2.2y2
ozzi

Answer:10x^2y^2

Step-by-step explanation:

5x2 X 2y2=10x^2y^2

3 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
3 years ago
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