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2 years ago

14

Translate this phrase into an algebraic expression. 62 less than twice a number Use the variable n to represent the unknown numb

er.

1 answer:

Vikentia [17]2 years ago

4 0

Answer:

62<2x

Step-by-step explanation:

You might be interested in

What are the major arcs of o0 that contain point B?

bixtya [17]

Answer:

see below

Step-by-step explanation:

The four major arcs that include B will be the remainder of the circle after each minor arc is excluded.

Excluding minor arc AB, we have major arc BCA.

Excluding minor arc BC, we have major arc CDB.

Excluding minor arc CD, we have major arc DAC.

Excluding minor arc DA, we have major arc ABD.

8 0

2 years ago

Leo is constructing a tangent line from point Q to circle P. What is his next step? circle P and point Q on the outside of circl

xxMikexx [17]

Answer:

The correct option is;

Construct a circle from point R with the radius RP

Step-by-step explanation:

To draw a tangent, the following steps are required

1) A line is drawn connecting the point to the center of the circle to which the tangent is to be drawn

2) The perpendicular bisector of the line constructed to get the mid point of the line

3) From the midpoint of the line found in the step above the compass is adjusted to reach the center of the given circle and a circular arc is drawn across the circumference of the given circle

4) The point of intersection of the arcs and the circumference of the given circle are the tangent points

Therefore, the correct option is to construct a circle from point R with the radius RP.

3 0

2 years ago

Wich fraction names the shaded part of the figure below

loris [4]

$\huge\boxed{\text{A.}\ \frac{1}{3}}$

There are $2$ shaded parts and $6$ total parts.

Write this as a fraction.

$\frac{2}{6}$

Simplify the fraction.

$\frac{2}{6}=\frac{2\div 2}{6\div 2}=\boxed{\frac{1}{3}}$

3 0

2 years ago

I need help with this, I don't understand this

Rudiy27

If you are trying to find the plot you go up as meany numbers as it says and then go over as meany numbers as it says.

8 0

2 years ago

Which equation could be solved using this application of the quadratic formula?

Alex_Xolod [135]

Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0 <em>This is not it!</em>

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0 <em>This is not it!</em>

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0 <em>This is it!</em>

Answer: C. x^2 + 2x - 1 = 3

8 0

2 years ago