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2 years ago

I need help in this question

Mathematics

2 answers:

iren [92.7K]2 years ago

6 0

Answer:

128

Step-by-step explanation:

Luda [366]2 years ago

4 0

Answer:

128 correct me if Im wrong

Step-by-step explanation:

To write it out you would write 2 x 2 x 2 x 2 x 2 x 2 x 2= and that equals 128

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The function f(x) is shown below.

Elenna [48]

The value of f(g(2)) is 2.

<h3>What is function?</h3>

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

The given table is

x f(x)

–6 1

–3 2

2 5

5 3

8 0

If the coordinates of a function f(x) is defined as (x,y)

then, the coordinates of inverse of f(x) is defined as (y,x).

f(g(y))= f(x) [ g(x)= (y,x)]

f(g(y))= y

So, If g(x) is the inverse of f(x), the f(g(y)) = y.

Also, we know g(x) is the inverse of f(x), then f(g(2)) = 2.

Learn more about this concept here:

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1 year ago

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let $\mu$ = true average percentage of organic matter

So, Null Hypothesis, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean percentage of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, the test statistics = $\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }$ ~ $t_2_9$

= -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

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3 years ago

What is blank/11 = 12/44 equivalent fractions

nordsb [41]

Answer:

3/11

Step-by-step explanation:

8 0

1 year ago

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kondor19780726 [428]

Hmm I’ve done this before but I can’t remember sorry but I will try and think

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2 years ago

When you woke up this morning, the temperature was −3.4°C. At bedtime, the temperature was 1.7°C. Which expression and statement

Sever21 [200]

Answer:

c, the third answer

Step-by-step explanation:

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2 years ago