Quarters = x
dimes = 196 - x
10(196 - x) + 25x = 3940
1960 - 10x +25x = 3940
1960 + 15x = 3940
15x = 1980
x = 132
169 - 132 = 64
Therefor there are 132 quarters and 64 dimes
Answer:
(a;b)={(17; 64); (64; 17)}
Step-by-step explanation:
a+b=81 => b=81-a
a*b=1088
a*(81-a)=1088
-a²+81a=1088
a²-81a+1088=0
a²-64a-17a+1088=0
a(a-64)-17(a-64)=0
(a-17)(a-64)=0
=> a=17 and a=64
for a=17 => b=81-17=64
for a=64 => b=81-64=17
(a;b)={(17; 64); (64; 17)}
We can solve this problem by the rule of three.
1000 protons=10³ protons
1 proton------------------2.53*10⁻³⁷g
10³ protons---------- x
x=(10³ protons * 2.53*10⁻³⁷) / 1 proton=2.53*10⁻³⁷⁺³ protons=
=2.53*10⁻³⁴ protons
answer: 2.53*10⁻³⁴ protons
The answer is 56%
You first divide 28 by 50=.56, then since it's a decimal, you move the decimal twice to the right to make a percentage=56%
Seventy-three is the answer
