3x - 5 + 2x = 15+ 4x - 5
5x - 5 = 10 + 4x
5x - 5 + 5 = 10 +5 +4x
5x = 4X + 15
5x - 4x = 4x - 4x + 15
x = 15
<h3>f(x)=3x³-13x²-3x+45</h3><h3>f(x)=3x³-9x²-4x²+12x-15x+45</h3><h3>f(x)=3x²(x-3)-4x(x-3)-15(x-3)</h3><h3>f(x)=(x-3)(3x²-4x-15)</h3><h3>f(x)=(x-3)(x-3)(3x+5)</h3><h2>f(x)=(x-3)²(3x+5)</h2>
<h3><u>Roots:</u></h3><h3>x=3</h3><h3>x=-5/3</h3>
Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
Answer:
ok
Step-by-step explanation:
9+10=21
