Answer:
he has 10 type of each coin
Step-by-step explanation:
Total number of cents in possession is calculated as;
= 25 + 10 + 5
= 40 cent
Total amount in possession = $4
= 400 cent
Since he has equal number of each cent, let this equal number be "y";
40cent (y) = 400cent
40y = 400
divide both sides by 40
Therefore, he has 10 type of each coin
Since , by the remainder theorem this means that <em>x</em> - 6 divides <em>f(x)</em> exactly. This means there are constants <em>a</em>, <em>b</em>, and <em>c</em> such that
Multiplying both sides by <em>x</em> - 6 gives
Then <em>a</em>, <em>b</em>, <em>c</em> satisfy
and solving this system gives <em>a</em> = 2, <em>b</em> = -7, and <em>c</em> = 3.
So, we have
The quadratic term can be factored as
which leaves us with
so that the zeros of <em>f(x)</em> are 6, 1/2, and 3.
