Question

Can someone help me asapp !!!!

Answer 1

Answer:

he has 10 type of each coin

Step-by-step explanation:

Total number of cents in possession is calculated as;

= 25 + 10 + 5

= 40 cent

Total amount in possession = $4

                                               = 400 cent

Since he has equal number of each cent, let this equal number be "y";

40cent (y) = 400cent

40y = 400

divide both sides by 40

$\frac{40y}{40} = \frac{400}{40} \\\\y = 10$

Therefore, he has 10 type of each coin