First one is
(2x+5)
Second one is
“All of these are correct”
Hope this helped
Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
The first two negatives cancel out and you're left with positive 4. Now go inside the square root and do the exponent. -4*-4 = 16. Then do the -4*3*1 = -12. Do 16-12 = 4. now the square root of 4 = 2. at the dominator is 2*3 = 6. right now they problem should look like 4+- 2/ 6. from there you split the problem in two. so you have 4+2/6 & 4-2/6 then you solve both problems.
6/6 2/6
1 1/3
1 & 1/3 are your answers. I hope this helped!
720% is your answer! Think of it as money! 1/5 out of 100 is 20 cents, 7 is 7 dollars. 720 pennies all together so 720%! Hope this helps.
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