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3 years ago

Need help on these questions ASAP DUE TOMORROW PLEASE

Mathematics

1 answer:

Shkiper50 [21]3 years ago

3 0

9514 1404 393

Answer:

3) D

4) D

5) B

6) B

Step-by-step explanation:

3) A "Pythagorean triple" is a set of 3 integers that could be the sides of a right triangle. The only triangle shown with integer side lengths is choice D.

5) The only triangle for which the square of the hypotenuse is the sum of the squares of the other two sides is choice D.

11² +2² = (5√5)²

121 + 4 = 125

6) The lengths of sides of each right triangle are 2/3 of those of choice D in problem 4. That is, they are a 7-24-25 triangle, multiplied by 2. That means the height is 24·2 = 48, and the area is ...

A = 1/2bh

A = 1/2(28 m)(48 m) = 672 m² . . . . matches choice B

7) The side lengths of a 30-60-90 triangle have the ratios 1 : √3 : 2. That is, the short leg is half the hypotenuse, a fact stated in A and D. Those true statements make it clear that statement B is false.

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Movies are on sale for 3/4 the original price. If the original price is $16, what is the sale price?

Nesterboy [21]

If the original price is 16, then 3/4 of 16 is 12.

$12

Dividing 16 by 4 (the denominator), you get 4. Then 4 x 3 (the numerator) is 12.

5 0

3 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

2 years ago

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Graph the image of the figure using the dilation given)

Anni [7]

Answer:

v' (0.5,1) , u' (0,1) , t' (-0.5,0) , w' (-0.5, -1)

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2 years ago

Solve the system of equations - 6x + 8y = –10 and - 4x + y = –11 by<br> combining the equations.

elena55 [62]

Answer: (3, 1) :)

Explanation:
-6x + 8y = -10
-4x + y = -11
-32x + 8y = -88
26x = 78
x = 3
-18 + 8y = -10
8y = 8
y = 1

(Also, can I have brainliest please?)

5 0

2 years ago

Can someone help me with these 2 questions real quick?

k0ka [10]

Answer:

<M = 32 and <Y = 103

Step-by-step explanation:

1. Since triangle BCM is congruent to triangle ZYR, we know the corresponding parts of the triangles are congruent. Therefore, <Z = <B = 45. The sum of a triangle’s angles is 180, so <M = 180 - <B - <C = 180 - 45 - 103 = 32

2. This is the exact same diagram, so we can use the information we have collected in #1. Since corresponding parts of congruent triangles are congruent, <Y must be congruent to <C, which equals 103. Therefore, <Y = 103.

I hope this helps! :)

8 0

2 years ago

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