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kvasek [131]
3 years ago
13

Need help on these questions ASAP DUE TOMORROW PLEASE

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

9514 1404 393

Answer:

  3)  D

  4)  D

  5)  B

  6)  B

Step-by-step explanation:

3) A "Pythagorean triple" is a set of 3 integers that could be the sides of a right triangle. The only triangle shown with integer side lengths is choice D.

__

5) The only triangle for which the square of the hypotenuse is the sum of the squares of the other two sides is choice D.

  11² +2² = (5√5)²

  121 + 4 = 125

__

6) The lengths of sides of each right triangle are 2/3 of those of choice D in problem 4. That is, they are a 7-24-25 triangle, multiplied by 2. That means the height is 24·2 = 48, and the area is ...

  A = 1/2bh

  A = 1/2(28 m)(48 m) = 672 m² . . . . matches choice B

__

7) The side lengths of a 30-60-90 triangle have the ratios 1 : √3 : 2. That is, the short leg is half the hypotenuse, a fact stated in A and D. Those true statements make it clear that statement B is false.

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Point A is (-7, 5) and point M is at (0, 4)
Tom [10]

Answer: (7,3)

Step-by-step explanation:

7 0
3 years ago
L.c.m of 21,24,26 what is it plz I need answers​
S_A_V [24]

Answer:

LCM of 21,24 and 26 is 2184

Step-by-step explanation:

We need to find LCM of 21,24 and 26

For finding LCM divide the given numbers by a prime number if two of the numbers are divisible by that prime number

 2  |    21,24,26

 2  |    21,12,13

 2  |   21,6,13

 3  |    21,3,13

 7  |   7,1,13

13  |   1,1,13

      |   1,1,1

So, LCM of 21,24 and 26 is: 2 x 2 x 2  x 3 x 7 x 13 = 2184

8 0
3 years ago
Help me in this pls
Komok [63]

Answer:

A, F, and C are the correct options.

Step-by-step explanation:


4 0
3 years ago
7s^0t^-5/2^-1m^2 Simplify
expeople1 [14]

Answer: hope this helps

6 0
2 years ago
Find the particular solution of the differential equation dy + 7y = 6 satisfying the initial condition y(0) = 0. Answer: y= Your
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

We have the equation y'+7y=6 with the initial condition y(0)=0. It is not difficult to notice that this is a linear equation, which has the general expression

y'+P(x)y=Q(x).

The solution of this equation is expressed by a general formula:

y(x) = \exp\left(-\int P(x)dx\right)\left(\int Q(x)\exp\left(-\int P(x)dx\right) +C\right).

In the particular case of our equation, we have

P(x)=7

Q(x)=6.

Then, we must calculate the integrals

\int 7dx = 7x that implies

\exp\left(-\int P(x)dx\right) = e^{-7x},

and

\int 6e^{7x}dx = \frac{6}{7}e^{7x}

Then,

y(x) = e^{-7x}\left(\frac{6}{7}e^{7x} +C\right) = \frac{6}{7} + Ce^{-7x}.

In order to obtain the value of the constant we substitute the initial condition

0=y(0) = \frac{6}{7} + C that implies C=-\frac{6}{7}

Therefore,

y(x) = \frac{6}{7}-\frac{6}{7}e^{-7x}.

8 0
3 years ago
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