Neither set of choices is correct.
If the distance is tripled, then the forces decrease to
1/9 Fg. and. 1/9 Fe.
Note. When the objects are charged, the gravitational force Fg can almost always be ignored, since Fe is like 10^40 greater when the quantities of mass and charge are similar.
Answer:
Explanation:
See the attachment for the details. A right triangle is formed to find the hypotenuse of the two legs consisting of the actual driving distances and times. The hypotenuse gives the vector information for the displacement at the end of 8 hours of driving.
The individual driving times and distances are summed to provide:
(<u>a) How far did he travel?</u>
103 km
<u>(b) What was his average speed?</u>
12.88 km/h
<u>(c) What was his displacement?</u>
73.82 km
<u>(d) What was his average velocity?</u>
9.228 km/h
Answer:
Slope = 2 m / 10 m = 1/5
For every 5 m of effort the object will be raised 1 m
W = work done on object = M g h increase in PE of object
E S = W where E is effort and S the distance thru which the effort acts
E S = M g H
E = 100 kg * 9.8 m/s^2 * 2 m / 10 m = 196 kg m / s^2 = 196 N
Check: total work = 2 * 9.8 * 100 = 1960 J
Force Needed = 1960 J / 2 m = 980 Newtons
Mechanical advantage = 980 / 196 = 5 as one would expect since the object is raised 1 m for every 5 m of force input
Answer:
B:The breakdown of rocks into smaller rocks
Explanation:
Physical weathering is breaking down rocks, but it doesn't change what the rock is made out of.
Answer:
I = 3.9 x 10⁷ W/m²
Explanation:
given,
Sheet of black paper dimension = 8.5 x 11 inch
Area of sheet = 8.5 x 11 = 93.5 inch^2
1 inch =0.0254 m
Area = 0.06032 m²
mass of sheet = 0.80 g
Force = m g = 0.8 x 9.8 x 10⁻³ N
= 7.84 x 10⁻³ N
speed of light = c = 3 x 10⁸ m/s
Using equation

where I is the intensity of light



I = 3.9 x 10⁷ W/m²
Intensity of the light is equal to I = 3.9 x 10⁷ W/m²